Question

dived 1000 rupees in the ratio 3:2

a)900 and 100

b)500 and 500

c)700 and 300

d)600 and 400
​

Answer 1

Required Solution:

${\underline {\boxed {\Large {\bf \purple{ Option \: D!} }}}}$

Here, we have to divide Rs. 1000 in the ratio of 3:2. So, firstly let us assume the parts as 3x and 2x respectively. (here,x is constant natural number).

Now, let's form an algebraic equation in order to find the value of x and the value of the parts.

According to the question,

$\longrightarrow \sf { 3x +2x = 1000 }$

• Forming a linear equation.

$\longrightarrow \sf { 5x = 1000 }$

• Performing addition.

$\longrightarrow \sf { x = \dfrac{1000}{5} }$

• Transposing 5 from LHS to RHS.

$\longrightarrow \sf \red { x =200 }$

So, the value of x is 200.

Now, calculating parts :

$\longrightarrow \sf { First \: part = 3x}$

$\longrightarrow \sf { First \: part = 3(200)}$

$\longrightarrow \sf \red { First \: part = 600}$

Also,

$\longrightarrow \sf { Second \: part = 2x}$

$\longrightarrow \sf { Second \: part = 2(200)}$

$\longrightarrow \sf \red { Second \: part = 400}$

Henceforth,

• Option D is correct. ( 600 & 400 )

Answer 2

Answer is d) 600 and 400