dived 400 into two parts such that 1/3 of the first part is 40 less than the other part. find the two parts
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Answer:
Let one part be x.
Another part = 84-x
Now,
As per the question ,
1/3 * x = 1/4 * (84-x)
x/3 *4 = 84-x
4x = 3(84-x)
7x = 84*3
x = 12*3 = 36
So, The two parts will be 36 and 84-36 i.e. 48.
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hdonadaun:
sorry
Let the first part be x and the second part be y.
Hence, 1/3x = y-40
And, y= 1/3x + 40
Therefore, (1/3x + 40)+ x = 400
1/3x + x = 360
4/3x = 360
x = 360* 3/4
x = 270 ( first part )
y = 1/3x + 40 = 130
Hence, 1/3x = y-40
And, y= 1/3x + 40
Therefore, (1/3x + 40)+ x = 400
1/3x + x = 360
4/3x = 360
x = 360* 3/4
x = 270 ( first part )
y = 1/3x + 40 = 130
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