Question

diverging lens of focal length 30 forms the image of an object of size 6 on the same side as the object at the distance of 15 cm from its optical Centre use lens formula to determine the distance of the object from the lens and the size of the image formed​

Answer 1

Answer:

30 is the and the size will be 3cm!

Answer 2

The distance of the object from the lens is -30 cm.

The size of the image formed​ is 3 cm.

Given:

f = -30 cm (Diverging lens)

v = -15 cm (Image and lens are in the same side)

Explanation:

By using Lens formula,

1/f = 1/v - 1/u

On substituting the known values, we get,

-1/30 = -1/15 - 1/u

-1/30 + 1/15 = -1/u

1/30 = -1/u

∴ u = -30 cm

Now, the magnification is given by the formula,

m = v/u = h'/h

h' = (v/u)h

On substituting the values, we get,

h' = (-15/-30)6

∴ h' = 3 cm