Question

divide 1/3 x^2 by -2/9x​

Answer 1

Step-by-step explanation:

$\frac{ \frac{1}{3} {x}^{2} }{ \frac{ - 2}{9}x }$

$= \frac{ {x}^{2} }{3} \times \frac{9}{ - 2x}$

$= \frac{ - 3x}{2}$

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