Question

Divide 1.50/1.44 what is the refractive index with benzene with respect to kerosene

Answer 1

h = 5 cm      u = ?    v = -15 cm     f = - 20  cm

    1/v - 1/u = 1/f          =>  1/u = 1/v - 1/f = -1/15 +1/20 = -1/60

          u = -60 cm        

            m = h'/h = v/u = -15/-60 = 1/4

              h' = 5/4 cm