Math, asked by mohdmurtaja14, 4 months ago

Divide:-
1+y3 by 1+y

Answers

Answered by sudhanshupathak450
0

Answer:

Find

(1+y)

(1+y

3

)

\begin{gathered} \frac{(1+y^{3})}{(1+y)} \\= \frac{1^{3} + y^{3}}{(1+y)} \\= \frac{(1+y)( 1^{2} - 1 \times y + y^{2})}{(1+y)} \end{gathered}

(1+y)

(1+y

3

)

=

(1+y)

1

3

+y

3

=

(1+y)

(1+y)(1

2

−1×y+y

2

)

\underline {\blue { By \: Algebraic \:Identity }}

ByAlgebraicIdentity

\boxed {\pink { a^{3} + b^{3} = (a+b)(a^{2} -ab + b^{2}) }}

a

3

+b

3

=(a+b)(a

2

−ab+b

2

)

= 1 - y + y^{2}=1−y+y

2

Therefore.,

\red { \frac{(1+y^{3})}{(1+y)}} \green {= 1 - y + y^{2} }

(1+y)

(1+y

3

)

=1−y+y

2

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