Divide:-
1+y3 by 1+y
Answers
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0
Answer:
Find
(1+y)
(1+y
3
)
\begin{gathered} \frac{(1+y^{3})}{(1+y)} \\= \frac{1^{3} + y^{3}}{(1+y)} \\= \frac{(1+y)( 1^{2} - 1 \times y + y^{2})}{(1+y)} \end{gathered}
(1+y)
(1+y
3
)
=
(1+y)
1
3
+y
3
=
(1+y)
(1+y)(1
2
−1×y+y
2
)
\underline {\blue { By \: Algebraic \:Identity }}
ByAlgebraicIdentity
\boxed {\pink { a^{3} + b^{3} = (a+b)(a^{2} -ab + b^{2}) }}
a
3
+b
3
=(a+b)(a
2
−ab+b
2
)
= 1 - y + y^{2}=1−y+y
2
Therefore.,
\red { \frac{(1+y^{3})}{(1+y)}} \green {= 1 - y + y^{2} }
(1+y)
(1+y
3
)
=1−y+y
2
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