Question

divide 10 x power 4 + 17 x cube - 62 X square + 30x minus 3 by 2 X square + 7 x minus one​

Answer 1

Hope this helps you. .

- Khushali.S.S.

Answer 2

Given :

Dividend =$10x^4+17x^3-62x^2+30x-3$

Divisor = $2x^2+7x-1$

To Find :

Divide

Solution:

Dividend =$10x^4+17x^3-62x^2+30x-3$

Divisor = $2x^2+7x-1$

$Dividend = (Divisor \times Quotient)+remainder\\10x^4+17x^3-62x^2+30x-3=((2x^2+7x-1) \times 5x^2)+(-18x^3-57x^2+30x-3)\\10x^4+17x^3-62x^2+30x-3=((2x^2+7x-1) \times 5x^2-9x)+(6x^2+21x-3)\\10x^4+17x^3-62x^2+30x-3=((2x^2+7x-1) \times 5x^2-9x+3)+0$

Hence the solution is $5x^2-9x+3$