Divide 10(x3y2x2 + x2y3z2 + x2y2z3) by 5x2y2z2.
Answers
Answered by
73
10(x³y²z² + x²y³z² + x²y²z³) by 5x²y²z²
firstly multiply 10 with brackets
means open a bracket
( 10x³y²z² + 10x²y³z² + 10x²y²z³ ) / 5x²y²z²
= (10x³y²z²)/5x²y²z² + (10x²y³z²)/5x²y²z² + (10x²y²z³)/5x²y²z²
= 2x + 2y + 2z
firstly multiply 10 with brackets
means open a bracket
( 10x³y²z² + 10x²y³z² + 10x²y²z³ ) / 5x²y²z²
= (10x³y²z²)/5x²y²z² + (10x²y³z²)/5x²y²z² + (10x²y²z³)/5x²y²z²
= 2x + 2y + 2z
Answered by
18
Answer:
10 (x3y2x2+x2y3z2+x2y2z3)=2(x3yz3)
Step-by-step explanation:
10x3y2x2÷5x2y2z2+10x2y3z2÷5x2y2z2+10x2y2z3÷5x2y2z2=
2x3z2+2y+2z then
2 (x3yz3)
The problem is solved
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