Question

Divide 10000 into two parts such that 40% of one part is greater than 50% of the other part by 400. (Give step by step solution)​

Answer 1

Answer:

x = 5560

y = 4440

Step-by-step explanation:

Let the numbers be x and y

40x - 50y = 400

Taking 10 as common

10(4x - 5y) = 400

4x - 5y = 400/10

4x-5y = 40

4x = 40 + 5y

x = 40+5y/4

So we found the value of x

Substituting 40+5y/4 as x

x + y = 10000

(40+5y/4) + y = 10000

Taking 4 as common denominator

(40 + 5y + 4y/4)=10000

40 + 9y/4 = 10000

40 + 9y = 10000x4

40 + 9y = 40000

9y = 40000 - 40

9y = 39960

y = 39960/9

y = 4440

So x + y = 10000

y = 4440

x + 4440 = 10000

x = 10000 - 4440

x = 5560

Answer 2

Answer:

the amount has to be divides =Rs.10000

Let Rs x be the first part

Then, second part =Rs.(10000−x)

Interest on first part =100x×12×4=Rs.2512x

Interest on second part

=(10000−x)×10016×4.5

⇒Rs.(7200−2518x)

According to question,

⇒2512x=7200−2518x

⇒2512x+2518x=7200

⇒2530x=7200

⇒x=307200×25=Rs.6000

Second part =10000−6000