Question

Divide 105 into two parts such that one-half of the first exceeds one-fifth of the second part by 35​

Answer 1

Answer:

Verification 3*45 – 2*60 = 135 – 120 = 15

Step-by-step explanation:

From the above question, divide 105 into two parts such that one-half of the first exceeds one-fifth of the second part by 35​:

Let the greater number by X and smaller number be Y,

Therefore,

X+Y=105 → X=105-Y

Two times the greater part is 15 less than three times the smaller part

Here, one-half of the first exceeds one-fifth of the second part by 35​ :

         3Y - 2X = 15

         3Y - 2(105 - Y) = 15

         3Y - 210 + 2Y = 15

         5Y = 225

         Y = 45

         X = 105 - Y

            = 105 – 45 = 60

Verification:

3*45 – 2*60 = 135 – 120 = 15

Hence, while dividing 105 into two parts such that one-half of the first exceeds one-fifth of the second part by 35​ we will get 15.

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