Question

Divide* 108 among A, B and C in ratio 3:4:5
(a) *25, 45, 29 Hey 27, 36, 45
(c) * 36, 45, 25 (d) * 28, 38, 40​

Answer 1

let 3 ratio be 3x

let 4ratio be 4x

let 5ratio be 5x

add them

5x+4x+3x=108

12x =108

x=9

3x=3×9= 27

4x =4×9=36

5x=5×9=45

the correct option is b

Answer 2

Question :-

Divide 108 among A, B and C in ratio 3 : 4 : 5.

a] 25, 45, 29

b] 27, 36, 45

c] 36, 45, 25

d] 28, 38, 40

Answer :-

Given :

• Amount = 108
• Ratio = 3 : 4 : 5

Solution :

Let the amount of A be '3x', B be '4x' and the amount of C be '5x' respectively.

According to question,

$\sf\longrightarrow 3x + 4x + 5x = 108$

$\sf\longrightarrow 12x = 108$

$\sf\longrightarrow x = \dfrac{108}{12}$

$\sf\therefore x = 9$

Now,

Amount of A => 3x = 3 × 9 = 27

Amount of B => 4x = 4 × 9 = 36

Amount of C => 5x = 5 × 9 = 45

Therefore, the amount divided in the ratio 3 : 4 : 5 will be 27, 36 and 45.

Hence, b] 27, 36, 45 is the correct option.