Divide : 10x(6x + 21) by 5(2y + 7)
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We first factorise
10y (6y + 21)
= 10y [(3 x 2) y + (3 x 7)]
Taking 3 common,
= 10y x 3 (2y +7)
Dividing,
10y (6y +21)
5 (2y +7)
10y x 3(2y + 7) 5×(2y+7)
Step-by-step explanation:
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