Question

Divide 110 into two parts such that one-
third of the first part exceed one-seventh of
the second by 10​

Answer 1

Answer:

54 and 56

Step-by-step explanation:

lets divide 110 into two parts : x and y

then x+y = 110 ............(i)

according to question :

x/3 =y/7 +10

x/3 = (110-x)/7 +10 .............. using (i)

solving the above : x=54 and later y=56 .