Question

divide ₹1144 among A, B and C so that A receives 4/7 of what B and C together receive and B receives 2/9 of what A and C together receive.​

Answer 1

Answer:

Let x be share of A

Let y be share of B

Let z be share of C

Given x + y + z = 1144

Also given $\frac{4}{7} (y+z) = x$

$y+z = \frac{7x}{4}$

And $\frac{2}{9}(x+z) = y$

$x+z = \frac{9y}{2}$

The very first equation becomes:

x + (7x/4) = 1144

11x/4 = 1144

x= 416

An alternate form of the first equation is:

y + (9y/2) = 1144

11y/2 = 1144

y = 208

This gives us z = 1144 - (416+208)

z = 520

Therefore A gets Rs 416

B gets Rs 208

C gets Rs 520

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