Question

Divide 12.5 into 5 parts such that the first part and last part are in the ratio 2:3.

Answer 1

Answer:

2,2.25,2.5,2.75,3

Step-by-step explanation:

If first part = 2x,

fifth part = 3x

So, AP = 2x, 2x+d, 2x+ 2d, 2x+3d, 3x ( d is common difference)

The sum of these terms = 11x + 6d = 12.5 ……. (1)

5th term = T5 = 2x + 4d = 3x

=> x = 4d

By putting the value of x in (1)

11 * 4d + 6d = 12.5

=> 50d = 12.5

=> d= 1/4 = 0.25

Since, x = 4d

=> x= 4*(1/4) = 1

So, 5 parts are …..

,AP = 2, 2.25, 2.5, 2.75, 3