Divide 12 into two parts such that the sum of their squares is 74.
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Refer to the attachment
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Hi.
Let x = one of the numbers
Then the other number = 12 - x
Sum of the squares is 74
x^2 + (12-x)^2 = 74
Solve for x:
x^2 + 144 - 24x + x^2 = 74
2x^2 - 24x + 70 = 0
x^2 - 12x + 35 = 0
Factor
(x-7)(x-5) = 0
So,the the numbers are 5 and 7 .
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