Question

Divide 120 into two parts such one - sixth of one part may exceed one-fourth of the other part by 10.

Answer should come 96 and 24 but you please solve it.

Don't give an irrelevant answer.

If you don't know than don't give an answer. ​

Answer 1

Let one part be x.

So,  other part = (120-x).

According to condition,

1/6x-1/4(120-x) = 10

or, x/6-(120-x)/4 = 10

or, {2x-3(120-x)}/12 = 10

or, (2x-360+3x)/12 = 10

or, 5x-360 = 10×12

or, 5x-360 = 120

or, 5x-360 = 120

or, 5x = 120+360

or, 5x = 480

or, x = 480/5

or, x = 96

So, one part  = x = 96,

and other part =  (120-x) = (120-96) = 24.

Hence, the two parts are 96  and 24.

Hope this helps you to get to your answer.

Answer 2

Answer:

numbers and the numbers for each of