Question

divide 120 into two parts such that one tenth of first part may exceed one fifth of second part by 2

Answer 1

Let the smaller number be x
Greater number=120-x
1/10(120-x)-1/5x=2
12-1/10x-1/5x=2
10=1/10x+1/5x
10= x+2x/10
10=3x/10
3x=100
x=100/3
120-x=120-100/3
=360-100/3
=260/3