Question

Divide 121x²yz by 11xy.​

Answer 1

Answer:

X+Y+Z=11550, where X=(4/5)Y & Y=(2/3)Z

So now,

Z+Y+X=11550

Z+(2/3)Z+(4/5)(2/3)Z=11550

15Z+10Z+8Z=11550(15)

33Z=173250

Hence,

Z=5250

So, Y=(2/3)Z= (2/3)5250=3500

And, X = (4/5)Y= (4/5)3500=2800

So the answer is Z-X= 5250–2800=2450

Z gets Rs.2450 more than X.