Math, asked by anu70424, 1 year ago

Divide 12a²+ax-6x² by 3a-2x

Answers

Answered by studentandstruggling
5

Answer: Quotient = 4a+3x

Step-by-step explanation:

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Answered by shadowsabers03
1

12a^2+ax-6x^2 \\ \\ 12a^2-8ax+9ax-6x^2 \\ \\ 4a(3a-2x)+3x(3a-2x) \\ \\ (3a-2x)(4a+3x) \\ \\ \\ $Hence divided. And obtained the quotient$\ (4a+3x)\ $and remainder 0. \\ \\ \\ \\ Thank you. :-)$ \\ \\ \\ \\ \\

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