Math, asked by namra0, 9 hours ago

divide 12x^3 - 22x^2 + 14x -12 by 2x -3​

Answers

Answered by priyanshuupadhyay271
0

Step-by-step explanation:

this is the prope solution

do further on your own if to find roots or zeroes

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Answered by sreepoojitha31977
0

Step-by-step explanation:

2x-3=0

x=3/2

substitute in the 12x^3 - 22x^2 + 14x -12 by 2x -3.

12(3/2)^3-22(3/2)^2+14(3/2)-12

12(27/8)-22(9/4)+7(3)-12

3(27/2)-11(9/2)+21-12

81/2-99/2+9

-18/2+9

-18/2+18/2=0

remainder is 0

with the long division method we will get quotient is

6x^2-2x+4

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