divide 12x^3 - 22x^2 + 14x -12 by 2x -3
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Step-by-step explanation:
this is the prope solution
do further on your own if to find roots or zeroes
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Step-by-step explanation:
2x-3=0
x=3/2
substitute in the 12x^3 - 22x^2 + 14x -12 by 2x -3.
12(3/2)^3-22(3/2)^2+14(3/2)-12
12(27/8)-22(9/4)+7(3)-12
3(27/2)-11(9/2)+21-12
81/2-99/2+9
-18/2+9
-18/2+18/2=0
remainder is 0
with the long division method we will get quotient is
6x^2-2x+4
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