Divide 12xy(9xsq-16ysq) by 4xy(3x+4y)?
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Answer:
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Answer = 12xy (9xsq - 16ysq ) ÷ 4xy (3x + 4y)
= 12xy (9xsq - 16ysq ) ÷ 4xy (3x + 4y) 3 {(3x)sq - (4y)sq} ÷ 3x + 4y
= 12xy (9xsq - 16ysq ) ÷ 4xy (3x + 4y) 3 {(3x)sq - (4y)sq} ÷ 3x + 4y = 3( 3x + 4y) ( 3x- 4y) ÷ ( 3x + 4y)
= 12xy (9xsq - 16ysq ) ÷ 4xy (3x + 4y) 3 {(3x)sq - (4y)sq} ÷ 3x + 4y = 3( 3x + 4y) ( 3x- 4y) ÷ ( 3x + 4y) = 3 ( 3x - 4y)
= 12xy (9xsq - 16ysq ) ÷ 4xy (3x + 4y) 3 {(3x)sq - (4y)sq} ÷ 3x + 4y = 3( 3x + 4y) ( 3x- 4y) ÷ ( 3x + 4y) = 3 ( 3x - 4y) = 9x - 12y
= 12xy (9xsq - 16ysq ) ÷ 4xy (3x + 4y) 3 {(3x)sq - (4y)sq} ÷ 3x + 4y = 3( 3x + 4y) ( 3x- 4y) ÷ ( 3x + 4y) = 3 ( 3x - 4y) = 9x - 12y