Math, asked by arnav00796, 2 months ago

Divide ₹1380 among Raman, Rohan and Rakhi so that the amount Raman receives is 5 times as much as Rakhi’s

share and is 3 times as much as Rohan’s share.​

Answers

Answered by niyatiinn
1

Answer:

Raman share = Rs 900

Rakhi share = Rs 180

Rohan share = Rs 300

Step-by-step explanation:

Given,

Total amount = Rs. 1380

Let Raman gets ' x ',

Rohan gets ' y '

Rakhi gets ' z ' share of the total amount

According to question,

x + y + z  = Total Amount

x + y + z = 1380.

Given,

Raman receives 5 times as much as Rakhi, that is,

x = 5 * y  

=> y = x / 5

Also it is given that,

He receives 3 times as much as Rohan's share , that is,

x = 3 * z  

=> z = x / 3

Substituting the values of y and z :

x + ( x/5 ) + ( x/3 ) = 1380

( 15x + 3x + 5x ) / 15 = 1380

23x / 15 = 1380

23x = 1380 * 15

23x = 20700

Dividing both sides by 23,

23x / 23 = 20700 / 23

x = 900

y = x / 5

= 900 / 5

= 180

z = x / 3

= 900 / 3

= 300

So,

x = 900 , y = 180, z = 300

Hence,

Raman share = Rs 900

Rakhi share = Rs 180

Rohan share = Rs 300

Answered by anilputhuparambilkum
0

Answer:

Raman gets rupees 900, rohan gets rupees 300 and Rakhi gets rupees 180

Step-by-step explanation:

Let ramans share be x. Rohans share will be x/3.Rakhis share will be x/5. Adding these three will be 1380. Solve it

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