Math, asked by dikshamehra2dec, 1 year ago

Divide ₹1380 among Raman,Rohan and Rakhi so that the amount Raman receives, is 5 times as much as rakhi's share and is 3 times as much as rohan's share

Answers

Answered by prashilpa
42

Answer:

Raman gets Rs. 900.

Rohan gets Rs. 300.

Rakhi Gets Rs. 180.

Step-by-step explanation:

Let us assume Raman gets X, Rohan gets Y and Rakhi gets Z.  

X + Y + Z = Total Amount = 1380.

X = 5 * Z  => Z = X / 5

X = 3 * Y  => Y = X / 3

X + X/3 + X/5 = 1380

23X/15 = 1380

X = 900.

Raman gets Rs. 900.

Y = X / 3 = 900/3 = 300

Rohan gets Rs. 300.

Z = X / 5 = 900 / 5 = 180

Rakhi Gets Rs. 180.

Answered by navja12
33

Answer:

Step-by-step explanation:

Total amount = Rs 1380

Let the share of Rakhi be 'x' and that of Rohan be 'y'.

Then, Raman receives 5x and 3y.

Hence, 5x=3y

Now, Raman's share + Rakhi's share + Rohan's share = Rs 1380

So, here two equations are formed, one in form of 'x' and other in form of 'y'.

5x+ x +  y = 1380 and 3y +x+y = Rs 1380

On solving the above equations, we get x=180.

Now put x=180 in 5x=3y, so, 5*180 = 3y, hence y = 300

Therefore, Raman's share = Rs 900, Rakhi's share = Rs 180, Rohan's share = Rs 300.

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