Question

Divide 1380 in two parts such that 1/3 of one part exceed 1/7 of other part by 80.

Answer 1

Let the parts be X and 1380-X
according to the question
$\frac{x}{3} - \frac{1380 - x}{7} = 80$
taking LCM and Solving we get
7x-3(1380-x)=80×21
7x-4140+3x=1680
10x=5820
x=582
1380-582= 798