Math, asked by vishalchandrashekar7, 16 days ago

Divide ( 14 a^3 + 12a^2 + 21a + 18 ) by ( 7a + 6 )​

Answers

Answered by Ayush1717
0

7a + 6 \sqrt{14 {a}^{3 +} } 12 {a}^{2}  + 21a + 18 \\ answer = 2 {a}^{2}  + 3

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