Question

Divide 14 x square + 19 x - 3 by 7x-1

Answer 1

quotient = 14x+21(or)
2x+3
and
remainder = 0

#LILY

Answer 2

$\huge{\mathcal{\underline{Solution:}}}$

Question :

14 x² + 19 x - 3 ÷ 7x - 1

Solution:

Refer to the attachment above .

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Here, we can also use reminder theorem :-

g(x) = 7x - 1 = 0

=> 7x = 1

=> x = 1/7

p(x) = 14 x² + 19 x - 3

$= > 14x {}^{2} + 19x - 3 \\ \\ = > \cancel{ 14 } \: {}^{2} \times \frac{1}{ \cancel{ \: 7} }\times \frac{1}{7} + 19 \times \frac{1}{7} - 3 \\ \\ = > \frac{2}{7} + \frac{19}{7} - 3 \\ \\ = > \frac{2 + 19 - 21}{7} \\ \\ = > \frac{21 - 21}{7} \\ \\ \bold{ = > 0.}$


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Thanks for the question!

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