Math, asked by tapasri1826, 7 months ago

Divide 140 into two parts such that one-third of one part may exceed one-seventh of another part by 10. Then find the largest part.

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Answers

Answered by krishbharati17
0

Answer:

Divide 184 in to two parts

Let the two parts be x, this the other part will be (184 - x).

such that one-third of one part may exceed one-seventh of the other part by 8?

(x/3) - (184 - x)/7 = 8

x/3 - (184 -x)/7 = 8

7x - 552 + 3x = 3 × 7 × 8

7x - 552 + 3x = 168

10x = 552 + 168

10x = 720

x = 720/10

x = 72

The one parts is 72

The other part is 184 - 72 = 112.

Answer The one parts is 72 and the other part is 112.

Answered by VKVivekkumar
3

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