Divide 140 into two parts such that one-third of one part may exceed one-seventh of another part by 10. Then find the largest part.
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Divide 184 in to two parts
Let the two parts be x, this the other part will be (184 - x).
such that one-third of one part may exceed one-seventh of the other part by 8?
(x/3) - (184 - x)/7 = 8
x/3 - (184 -x)/7 = 8
7x - 552 + 3x = 3 × 7 × 8
7x - 552 + 3x = 168
10x = 552 + 168
10x = 720
x = 720/10
x = 72
The one parts is 72
The other part is 184 - 72 = 112.
Answer The one parts is 72 and the other part is 112.
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