Question

Divide 140 into two parts such that one-third of one part may exceed one-seventh of another part by 10. Then find the largest part.

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Maths

Linear Equations in One Variable

Solving Linear Equations with Variable on Both Sides

Divide 184 into two parts s...

MATHS

Divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8.

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ANSWER

Let the two parts be x and 184−x.

According to the given condition, we have

3

x

=

7

1

(184−x)+8

⇒

3

x

=

7

184−x+56

.....[Taking LCM on RHS]

⇒

3

x

=

7

240−x

⇒7x=3(240−x) .....[On cross-multiplication]

⇒7x=720−3x

⇒7x+3x=720 .....[Transposing−3x to LHS]

⇒10x=720

⇒x=72

So, one part is 72 and other part is 184−72=112.