Divide 1419 into three parts such that the second number is 2/3rd of the first and third number is 4/5th of the second
Answers
Answered by
20
Hello..friend...
Its simple
Let the first number be x.
According to question..
== x+2/3 of x+ 4/5 of 2/3 of x =1419
== x+2x/3+8x/15 = 1419
== 15(x)+5(2x) +8x/15 = 1419
== 15x+10x+8x/15= 1419
== 33x/15 = 1419
== 33x=1419 x 15
== x =21285/33
== x=645
Therefore first number is 645..
Second number =2/3of 645=430..
Third number =4/5 of 430=344
The number on dividing 1419 are 645,430,and 344
Its simple
Let the first number be x.
According to question..
== x+2/3 of x+ 4/5 of 2/3 of x =1419
== x+2x/3+8x/15 = 1419
== 15(x)+5(2x) +8x/15 = 1419
== 15x+10x+8x/15= 1419
== 33x/15 = 1419
== 33x=1419 x 15
== x =21285/33
== x=645
Therefore first number is 645..
Second number =2/3of 645=430..
Third number =4/5 of 430=344
The number on dividing 1419 are 645,430,and 344
Answered by
4
Let the first number be 'x'
Hence, Second number = 2x/3
Third number = 4/5 (2x/3)
According to question,
x + (2x/3) + 4/5 (2x/3) = 1419
= (15x + 10x + 8x) / 15 = 1419
= 33x / 15 = 1419
= 33x = 94.6
= x = 94.6 / 33
= x = 2.866
Hence, the numbers are 2.866, 1.91066 and 1.528
And this proves the question is wrong
Anshkumar6p:
your answer is wrong
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