Divide: 14x^2+5x-3 by 7x-1
Answers
Answered by
1
here
given, 7x-1=0
7x=1
x=1/7
BY PUTTING VALUE x=1/7
we get ,
14×(1/7)^2+5×1/7-3
14×1/49+5/7-3
14/49-5/7-3
14-35/49- 3
-21/49-3
-3/7-3
-3-21/7
-24/7 answer
Answered by
3
Step-by-step explanation:
ANOTHER METHOD
7x-1=0
x=1/7
=14^2X+5X-3
{14(1/7)^2+5(1/7)-3
=2+5/7-3
=14+5-21
=19-21
=-2
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