Question

Divide 150 into 3 parts such that second no.is five sixth the first nd third number is four fifth the number .

Answer 1

Let x = the first number 
5x/6= the second number
(4/5)(5x/6) = the third number= 2x/3 
x+5x/6+2x/3 = 150
Multiply both sides by 6 to get
6x+5x+4x = 900

x = 900/15
x = 60 (first number)
2nd number:
5*60/6 = 50
3rd number:
4*50/5 = 40 
The numbers are 60, 50, and 40.

Answer 2

Let the three part be a, b and c

Given :

Sum = 150

                                   

Given part :

First part = 'x'

                                       

Second part = 5/6 of x

                    = 5x/6

                                           

Third part = 4/5 of 5x/6

                = 2x/3

                                         

To find :

We have to find

the value of 'x'

                                           

As we know that sum of

three part is 150

                                         

So,

   According to the question,

$\implies\dfrac{x+5x}{6}+\dfrac{2x}{3}=150\\\\\\\implies6x+5x+4x=6\times150\\\\\\\implies x=\dfrac{6\times150}{15}\\\\\\\implies\boxed{x=60}$

                                           

Now we are going to

find the value of First

part, second part and

the third part. By putting

the value of 'x'.

                                       

First part = x

              = 60

Second part = 5x/6

                    = 5 × 60 / 6

                    = 50

Third part = 2x/3

                = 2 × 60 /3

               =  40