Question

divide 150 into 3 parts such that the second number is five-sixth the first number and the third number is four-fifths the second.

Answer 1

let the first number be x
second no =5x/6
third no. = (4/5)×(5x/6)
ans= 60
50
40

Answer 2

Let the first no. be x.
2nd no. =y= 5x/6
3rd no.= 4y/5
a/q. x+5x/6+20x/30=150
30x+25x+20x ÷30=150
75x=150×30
x= 150×30÷75=60
No.s are 60, 50,40.