Question

divide 150 into three parts such that the second number is five-sixths the first and the third number is fourth-fifths the second ​

Answer 1

Answer:

60, 50, 40

Step-by-step explanation:

let the numbers be x, y, z

5x/6 = y

4y/5 = z ⇒ 4/5 × 5x/6 = z

x + y + z = 150

x + 5/6x + 4/5 × 5/6x = 150

$\frac{6x + 5x + 4x}{6}$ = 150

$\frac{15x}{6}$ = 150

x = 60

y = $\frac{5*60}{6}$ = 50

z = 150 - 60 - 50 = 40            

Answer 2

Answer:

Let, the first part be 'x'.

ATQ:

⇒second part=(5/6)x

&, third part = (4/5)×(5/6)x =(2/3)x

As, 150 is divided into 3 parts accordingly, therefore, the sum of the three parts must be equal to 150.

∴ (2/3)x+(5/6)x+x=150

⇒(4+6+5)x/6=150

or 15x/6=150

or 5x/2=150

Now, on cross multiplication, we get:

x=150×2/5

⇒x=60(first part)

⇒(5/6)x=(5/6)×60=50(second part)

⇒(2/3)x=(2/3)×60=40(third part)