Question

Divide 150 into three parts such that the second number is five – sixths the first and the third number is four – fifths the second.

Answer 1

Answer:

Let the 3 parts be a, b, and c

given:pat 1x

second part 5/6 of x is 5x/6

third part 4/50f second part

4/5 x 5x/6 =2x/3

sum of three parts is 150

x+5x/6+2x/3=150

6x+5x+4x =6 x 150

15x = 6 x 150

x =6 x 150 /15

= 60

three parts of 150 are respectively

The lengths are 60, 50, and 40

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Answer 2

Let the first number be x.

Second number = 5/6x

Third number = 4/5 * 5/6x

= 2/3x

The total of these no. should be 150.

So, x+ 5/6x+ 2/3x = 150

(6x + 5x +4x)/6 = 150

15/6x = 150

x = 150*6/15

x = 60

Therefore parts are 60, 50, 40.

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