Question

Divide 150 into three parts such that the second
number is five sixth of the first and third number
4/5 th of the second​

Answer 1

your ans

Let the 3 parts be a,b, and cGiven:First part:xsecond part 65 of x is 65x third part 54 0f second part= 54 × 65x = 32x sum of three parts is =150

⇒x+ 65x + 32x =150

⇒x+ 65x + 32x =150⇒6x+5x+4x=6×150

⇒x+ 65x + 32x =150⇒6x+5x+4x=6×150⇒15x=6×150

⇒x+ 65x + 32x =150⇒6x+5x+4x=6×150⇒15x=6×150⇒x=6× 15

150 =60

150 =60three parts of 150 are respectively

150 =60three parts of 150 are respectively First part=60

150 =60three parts of 150 are respectively First part=60Second part= 65 ×x= 65 ×60=50

×x= 65 ×60=50Third part=150−Sum of other two parts=150−(60+50)=40

∴The lengths are 60,50, and 40...

hope it will help you

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Answer 2

Answer:

$\fbox\red{ Wlcm bro.. }$