Question

divide 150 into three parts such that the second number is five-sixths the first and third number is four-fifths the second​

Answer 1

Answer:

60, 50,40

Explanation:

Here, second number (50) is five sixth the first (60) and third number (40) is four-fifths the second.

Answer 2

Step-by-step explanation:

Let the 3 parts be a,b, and c

Given:First part:x

second part 5/6 of x is 5x/6

third part 4/5 0f second part=4/5×5x/6= 2x/3

sum of three parts is =150

⇒x+ 5x/6+2x/3=150

⇒6x+5x+4x=6×150

⇒15x=6×150

⇒x=6×150/15=60

three parts of 150 are respectively

First part=60

Second part=5/6×x=5/6×60=50

Third part=150−Sum of other two parts=150−(60+50)=40

∴The lengths are 60,50, and 40