Question

Divide 150 into three parts such that the second part is 5/6 th of the first and the third part is 4/5 th of the second

Answer 1

Let first part be x

Then,

Second part = 5/6 × x =5x/6

Third part = 5x/6 × 4/5 = 2x/3

ATQ,

x + 5x/6 + 2x/3 =150

(6x+5x+4x)/6 =150

15x/6=150

x=150×6/15=60

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