Divide ₹1500 into two parts so that 10% of the larger part exceeds 8% of the smaller part by ₹60 .
Find the larger and smaller multiple.
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let parts be x any y
then
(10/100)x=(8/100)y+60
x/10=2y/25 +60. be first eq
sum of x,y =1500
x+y=1500
then
x=1500-y be second eq
sub first eq and second eq
then (1500-y)/10=(2y/25)+60
150-y/10 = (2y/25)+60
-y/10 = (2y/25)-90
-y/10-2y/25=-90
(5y+4y)/50=90
9y=4500
y=500
then x=1000
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