Question

Divide ₹1500 into two parts so that 10% of the largest part exceeds 8% of smaller part by ₹60. Find the value of larger and smaller part.​

Answer 1

Answer:-

Let the largest part be a

then the smallest part will become [ 1500 - a ]

According to question

10/100[ a ] - 8/100 [ 1500 - a ] = 60

10a/100 - [ 12000 - 8a ]/100 = 60

Take LCM on LHS side

[ 10a - 12000 + 8a ]/100 = 60

18a - 12000 = 60 × 100

18a - 12000 = 6000

18a = 6000 +12000

18a = 18000

a = 18000/18 = 1000

Therefore Largest part a = 1000.

smaller part = 1500 - a = 1500 - 1000 = 500.

Answer 2

Answer:

Divide ₹1500 into two parts so that 10% of the largest part exceeds 8% of smaller part by ₹60. Find the value of larger ...