Question

divide 1550 into 4 parts such that the second part is 50 more than the first third part is more than twice the first the fourth part is 50 less than the twice the first​

Answer 1

Given, that the second part is 50 more than the first third part is more than twice the first the fourth part is 50 less than the twice the first​

Let the first part be "x"

Second part is "50 + x"

Third part is "2x + x"

Forth part is "2x - 50"

1550 = (x) + (50+x) + (2x+x) + (2x - 50)

1550 = x + 50 + x + 2x + x + 2x - 50

1550 = x + x  + x + 2x + 2x

1550 = 3x + 4x

1550 = 7x

x = 221.43

Verification:

x + 50 + x + 2x + x + 2x - 50

= 221.43 + 50 + 221.43 + 2(221.43) + 221.43 + 2(221.43) - 50

= 221.43 + 221.43 + 2(221.43) + 221.43 + 2(221.43)

= 7 (221.43)

= 1550.01 ≈ 1550