Question

divide 16√6 by 4 √2 ....one more is there ...18√21 by 6√7

Answer 1

The first one :-

16root6 ÷4root2

The rules which are necessary to solve these kind of problems :-

The division process occurs separately for the constant term amd the root term.
Also,
We may need to break the roots into parts.
For example root18 can be broken into root2*root3 * root3 that means that root18 = 3root2 (since we habe to root3 in multiplication so we get a whole 3 from it)

Now,
Back to the question

16root6 = 16 root3*root2

This is divided by 4root2
Now
16root3*root2/4*root2
= 16*root3/4 (root2 gets canceled)
= 4root3

Second one :-

18root21 divided by 6root7
So,
18*root3 *root7 / 6*root7
= 18*root3/6
= 3 root3

Answer 2

Answer:

i think this is the answer

Step-by-step explanation:

3root3