Question

divide (16 a^4 - 32 a^3+ 16 a ^2) by -4a^2​

Answer 1

Answer:

$-4(a-1)^2$

Step-by-step explanation:

$\frac{16a^4 - 32 a^3 +16 a^2}{-4a^2}\\= \frac{16 a^4}{-4a^2} - \frac{32a^3}{-4a^2} + \frac{16 a^2}{-4 a^2}\\= -4 a^2 + 8a - 4\\= -4(a^2-2a+1)\\=-4(a-1)^2$

Answer 2

I hope it will help you