Question

divide 16 into two parts in which twice the square of the longer padivide 16 into two parts such that twice the square of the longer part exceeds the square of the smaller part by 164 ​​

Answer 1

Answer:

Let the larger part be x. Then, the smaller part =16−x

By hypothesis, we have

2x2=(16−x)2+164

⇒x2+32x−420=0⇒(x+42)(x−10)=0

⇒x=−42 or x=10

∵ x can not be a negative

⇒x=10

hence the required parts are 10 and (16−10)=6

Answer 2

Answer:

اشوء شلغشاشةضاوصتض اه ضاستصعاصعضسغاصعشاشتش

Step-by-step explanation:

وسعصا٧ضتض هل تصا١