Question

Divide 16 into two parts such that twice of square of larger part exceed square of smaller part by 164

Answer 1

Answer is 10,6

Step-by-step explanation:

let the numbers be x, y respectively

(x>y)

ATQ, x + y = 16

so, x=16-y ....... (1)

2(x)^2=y^2 + 164 (2)

putting value of x from (1) in (2)

=> 2(16-y)^2 =y^2 + 164

=> 2y^2 +512 -64y=y^2 + 164

when u simplify it, You get

=> y^2-64y+348=0

=> y^2-6y-58y+348=0

=> (y-6)(y-58)=0

so, y= 6 or y=58

y is less than 16

so, y=6

so, x =16-6= 10

is the solution correct?

Answer 2

Step-by-step explanation:

flw me

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