Question

Divide 16 into two parts such that twice the square of the larger part
exceed the square of the smaller part by 164.
PLZZ ANSWER AS SOON AS POSSIBLE..... PLZZ

Answer 1

let the smaller number be 'x'

then larger number=16-x

According to the question,

2×square of larger number=square of small number+164

2×(16-x)²=(x)²+164

2[(16)²+(x)²-2(16)(x)]=x²+164

2(256+x²-32x)=x²+164

512+2x²-64x=x²+164

2x²-x²-64x+512-164

x²-64+348=0

x²-58x-6x+348=0

x(x-58)-6(x-58)

x-6=0 or x-58=0

x=6 or x=58

when x=6,

smaller number=6

larger number=15-6=10

Hope it works..................................™✌️✌️

Answer 2

Refers to attachment ♡~