Divide 16 into two positive numbers such that twice the square of the larger part exceeds the square of the smaller part by 164. topic :Quadratic equation
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Answer:
answer is 6 and 10
Step-by-step explanation:
Let the larger part be x. Then, the smaller part =16−x
By hypothesis, we have
2x 2 =(16−x) 2 +164
⇒x2 +32x−420=0⇒(x+42)(x−10)=0
⇒x=−42 or x=10
∵ x can not be a negative
⇒x=10
hence the required parts are 10 and (16−10)=6
hope it helps u
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