Question

divide 16 into two positive unequal parts so that square of the smaller part is 3 more than twice the larger

Answer 1

Answer:

larger no. is 11 and smaller is 5.

Step-by-step explanation:

let us take x as the smaller no. therefore the larger no. will be 16-x.

16-x+x = 16

according to the question,

let x² = 2(16-x) + 3

= 32-2x+3

= 35-2x

x²- 35-2x = 0

x²-2x-35 = 0

x²+5x-7x-35 = 0

x(x+5)-7(x-5) = 0

therefore,

x-5 = 0. or x-7 = 0

x= 5 or. x= 7

try with x = 5 we get,

(16-5)+5=11+5=16

hence,

the larger no. is 11 and smaller is 5.

hope it helps you...