Question

Divide 160 into 2 equal parts so that four times the smaller one is equal to twice the larger one​

Answer 1

Answer:

Here is the answer of your question.

Answer 2

let smaller part be x and greater part become 4x

x+4x=160

5x=160

x=160/5

x=32

greater part=4×32

= 128

60x1.5x=x+1.5x=2.5x=602.5=24=36  

So the two parts are 24 and 36.

Let the smaller part be x

ATQ

X+4x=160

5x=160

X=160/5=32

One part is x=32

Let x and (16 - x) are two parts of 16 where (16 - x) is longer and x is smaller .

A/C to question,

2 × square of longer = square of smaller + 164

⇒ 2 × (16 - x)² = x² + 164

⇒ 2 × (256 + x² - 32x ) = x² + 164

⇒ 512 + 2x² - 64x = x² + 164

⇒ x² - 64x + 512 - 164 = 0

⇒ x² - 64x + 348 = 0

⇒x² - 58x - 6x + 348 = 0

⇒ x(x - 58) - 6(x - 58) = 0

⇒(x - 6)(x - 58) = 0

⇒ x = 6 and 58

But x ≠ 58 because x < 16

so, x = 6 and 16 - x = 10

Hence, answer is 6 and 10

Other =4x=4×32=128

Let the larger part be x. Then, the smaller part =16−x

By hypothesis, we have

2x  

2

=(16−x)  

2

+164

⇒x  

2

+32x−420=0⇒(x+42)(x−10)=0

⇒x=−42 or x=10

∵ x can not be a negative

⇒x=10

hence the required parts are 10 and (16−10)=6