divide 169 into two parts such that 5/7 of one part is greater than 3/5 of the other part by 9
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neerajomer:
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Answered by
36
Let one part be x
Therefore the other part is 169-x
Acc. to the question
5/7× (x)=3/5(169-x)+9
5/7×(x)= 507-3x/5 +9
5/7×(x)= 507-3x+45/5
5/7×(x)=552-3x/5
25/7×(x)=552_3x
25x=(552-3x)7
25x=3864-21x
46x=3864
x=3864÷46
x=84
Therefore the parts are 84 and (169-84)=85
Therefore the other part is 169-x
Acc. to the question
5/7× (x)=3/5(169-x)+9
5/7×(x)= 507-3x/5 +9
5/7×(x)= 507-3x+45/5
5/7×(x)=552-3x/5
25/7×(x)=552_3x
25x=(552-3x)7
25x=3864-21x
46x=3864
x=3864÷46
x=84
Therefore the parts are 84 and (169-84)=85
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